2x^2+8x-10=144

Solution for 2x^2+8x-10=144 equation:

2x^2+8x-10=144

We move all terms to the left:

2x^2+8x-10-(144)=0

We add all the numbers together, and all the variables

2x^2+8x-154=0

a = 2; b = 8; c = -154;
Δ = b2-4ac
Δ = 82-4·2·(-154)
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1296}=36$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-36}{2*2}=\frac{-44}{4}
=-11
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+36}{2*2}=\frac{28}{4}
=7
$